4sin^2x+1=4

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Solution for 4sin^2x+1=4 equation: 


Simplifying
4sin2x + 1 = 4

Reorder the terms:
1 + 4in2sx = 4

Solving
1 + 4in2sx = 4

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4in2sx = 4 + -1

Combine like terms: 1 + -1 = 0
0 + 4in2sx = 4 + -1
4in2sx = 4 + -1

Combine like terms: 4 + -1 = 3
4in2sx = 3

Divide each side by '4n2sx'.
i = 0.75n-2s-1x-1

Simplifying
i = 0.75n-2s-1x-1

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